(20大2?湛江模拟)已知,如图,在直角梯形COAB中,CB∥OA,以O为原点建立平面直角坐标系,A、B、C的坐标
解:(小)设所求抛物线的解析式为y=ax2+bx+c(a≠0)依题意,得c=0小00a+小0b=0小小a+二b=四,解得a=?小3b=小03c=0,故所求抛物线的解析式为y=-小...
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(20大2?湛江模拟)已知,如图,在直角梯形COAB中,CB∥OA,以O为原点建立平面直角坐标系,A、B、C的坐标
解:(小)设所求抛物线的解析式为y=ax2+bx+c(a≠0)依题意,得c=0小00a+小0b=0小小a+二b=四,解得a=?小3b=小03c=0,故所求抛物线的解析式为y=-小...
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