设复数z=cosθ+isinθ(0<θ<π), ω= 1- ( . z ) 4 1+ z 4 ,并且 |ω|
解法一ω=1-[cos(-θ)+isin(-θ)]41+[cosθ+isinθ]4=1-cos(-4θ)-isin(-4θ)1+cos4θ+isin4360问答θ=2sin22θ...
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1740÷x=720 6x×34=310 x÷89=78
(1)1740÷x=供够仅味香地促务通介7201740÷x×x=720x720x=740720x÷720=1740360问答÷720x=1740×720x=1714;(2)6x×...
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